What are the solutions to the equation 2x^2+4x+5=0 ?

The solutions to the equation 2x^2+4x+5=0 are x=-1+isqrt(3/2),x=-1-isqrt(3/2)

Find the zeros of 2x^2+4x+5=0

The zeros of 2x^2+4x+5=0 are x=-1+isqrt(3/2),x=-1-isqrt(3/2)

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2 x^{2} + 4 x + 5 = 0

x = - 1 + i \frac{3}{2}, x = - 1 - i \frac{3}{2}

Solution steps

2 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

4^{2} - 4 \cdot 2 \cdot 5 : 26 i

x_{1, 2} = \frac{- 4 \pm 2 6 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 2 6 i}{2 \cdot 2}, x_{2} = \frac{- 4 - 2 6 i}{2 \cdot 2}

x = \frac{- 4 + 2 6 i}{2 \cdot 2} : - 1 + i \frac{3}{2}

x = \frac{- 4 - 2 6 i}{2 \cdot 2} : - 1 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{3}{2}, x = - 1 - i \frac{3}{2}

77 r^{7} s^{7} - 84 r^{8} s^{4}

\frac{4}{12} + \frac{x}{9} = 1

3 y^{2} + 19 y + 30

6 x^{2} + 60 x = - 366

\frac{45 x ^{4} y}{9 x ^{6} y ^{3}}

What are the solutions to the equation 2x^2+4x+5=0 ?
The solutions to the equation 2x^2+4x+5=0 are x=-1+isqrt(3/2),x=-1-isqrt(3/2)
Find the zeros of 2x^2+4x+5=0
The zeros of 2x^2+4x+5=0 are x=-1+isqrt(3/2),x=-1-isqrt(3/2)