What are the solutions to the equation x^2-8x+64=0 ?

The solutions to the equation x^2-8x+64=0 are x=4+4sqrt(3)i,x=4-4sqrt(3)i

Find the zeros of x^2-8x+64=0

The zeros of x^2-8x+64=0 are x=4+4sqrt(3)i,x=4-4sqrt(3)i

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x^{2} - 8 x + 64 = 0

x = 4 + 43 i, x = 4 - 43 i

Solution steps

x^{2} - 8 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 64 : 83 i

x_{1, 2} = \frac{- ( - 8 ) \pm 8 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 3 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 3 i}{2 \cdot 1} : 4 + 43 i

x = \frac{- ( - 8 ) - 8 3 i}{2 \cdot 1} : 4 - 43 i

The solutions to the quadratic equation are:

x = 4 + 43 i, x = 4 - 43 i

(\frac{1}{36})^{x + 8} \leq 21 6^{x - 3}

\frac{8}{3} - 4

36 - 8

\frac{- 45 156}{9 3}

3 x^{2} + 4 x \leq 15

What are the solutions to the equation x^2-8x+64=0 ?
The solutions to the equation x^2-8x+64=0 are x=4+4sqrt(3)i,x=4-4sqrt(3)i
Find the zeros of x^2-8x+64=0
The zeros of x^2-8x+64=0 are x=4+4sqrt(3)i,x=4-4sqrt(3)i