What are the solutions to the equation 3(x+1)^2=108 ?

The solutions to the equation 3(x+1)^2=108 are x=5,x=-7

Find the zeros of 3(x+1)^2=108

The zeros of 3(x+1)^2=108 are x=5,x=-7

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3 (x + 1)^{2} = 108

x = 5, x = - 7

Solution steps

3 (x + 1)^{2} = 108

Divide both sides by

3

(x + 1)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 36 : x = 5

Solve

x + 1 = - 36 : x = - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

5 v - 6 > 9 v - 30

\frac{( 1 - i ) ^{2}}{( 1 + i ) ^{2}}

- (x + 2) = - 9

22 x - 16 = 4 x + 65

x^{2} + 7 x \leq 18

What are the solutions to the equation 3(x+1)^2=108 ?
The solutions to the equation 3(x+1)^2=108 are x=5,x=-7
Find the zeros of 3(x+1)^2=108
The zeros of 3(x+1)^2=108 are x=5,x=-7