What is sqrt(2x-1)<= 3 ?

The solution to sqrt(2x-1)<= 3 is 1/2 <= x<= 5

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sqrt(2x-1)<= 3

2 x - 1 \leq 3

\frac{1}{2} \leq x \leq 5

Interval Notation

[\frac{1}{2}, 5]

Decimal Notation

0.5 \leq x \leq 5

Solution steps

2 x - 1 \leq 3

Square both sides

(2 x - 1)^{2} \leq 3^{2}

Simplify

2 x - 1 \leq 9

2 x - 1 \leq 9 : x \leq 5

x \leq 5

Find singularity points

Find non-negative values for radicals:

x \geq \frac{1}{2}

Combine the intervals

x \leq 5 and x \geq \frac{1}{2}

Merge Overlapping Intervals

\frac{1}{2} \leq x \leq 5

510 \cdot \frac{π}{180}

1 = 7 - 3 x

- 0.1 x^{2} - x + 44 = 0.1 x^{2} + 2 x + 24

∣ x - 1 ∣ + ∣ x - 6 ∣ = 5

- 3.2 + 16.1 v = 17.32 + 17.3 v