What are the solutions to the equation 3x^2+14x+8=0 ?

The solutions to the equation 3x^2+14x+8=0 are x=-2/3 ,x=-4

Find the zeros of 3x^2+14x+8=0

The zeros of 3x^2+14x+8=0 are x=-2/3 ,x=-4

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3 x^{2} + 14 x + 8 = 0

x = - \frac{2}{3}, x = - 4

Decimal Notation

x = - 0.66666 \dots, x = - 4

Solution steps

3 x^{2} + 14 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 8 = 10

x_{1, 2} = \frac{- 14 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 10}{2 \cdot 3}, x_{2} = \frac{- 14 - 10}{2 \cdot 3}

x = \frac{- 14 + 10}{2 \cdot 3} : - \frac{2}{3}

x = \frac{- 14 - 10}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 4

49 a^{2} + 14 a + 1

\frac{18}{32}

\frac{9}{x - 4} + \frac{2 x}{x + 4} > - 1

\frac{72}{2}

(64 s^{\frac{3}{7}})^{\frac{1}{6}}

What are the solutions to the equation 3x^2+14x+8=0 ?
The solutions to the equation 3x^2+14x+8=0 are x=-2/3 ,x=-4
Find the zeros of 3x^2+14x+8=0
The zeros of 3x^2+14x+8=0 are x=-2/3 ,x=-4