What are the solutions to the equation x^2+7x-87=8x+3 ?

The solutions to the equation x^2+7x-87=8x+3 are x=10,x=-9

Find the zeros of x^2+7x-87=8x+3

The zeros of x^2+7x-87=8x+3 are x=10,x=-9

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x^{2} + 7 x - 87 = 8 x + 3

x = 10, x = - 9

Solution steps

x^{2} + 7 x - 87 = 8 x + 3

Move

3

to the left side

x^{2} + 7 x - 90 = 8 x

Move

8 x

to the left side

x^{2} - x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 90 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 90) = 19

x_{1, 2} = \frac{- ( - 1 ) \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 19}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 19}{2 \cdot 1}

x = \frac{- ( - 1 ) + 19}{2 \cdot 1} : 10

x = \frac{- ( - 1 ) - 19}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 10, x = - 9

\frac{2 ^{2}}{2}

6 = 2 (y + 2)

\frac{9 ^{- 3}}{9 ^{12}}

- \frac{1}{7} \cdot 7

2 - \frac{1}{3}

What are the solutions to the equation x^2+7x-87=8x+3 ?
The solutions to the equation x^2+7x-87=8x+3 are x=10,x=-9
Find the zeros of x^2+7x-87=8x+3
The zeros of x^2+7x-87=8x+3 are x=10,x=-9