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Popular >

3.1x^2-7.4x+3.2>0

Solution

3.1 x^{2} - 7.4 x + 3.2 > 0

Solution

x < 0.56721 \dots or x > 1.81988 \dots

+1

Interval Notation

(- \infty, 0.56721 \dots) \cup (1.81988 \dots, \infty)

Solution steps

3.1 x^{2} - 7.4 x + 3.2 > 0

Complete the square

3.1 x^{2} - 7.4 x + 3.2 : 3.1 (x - 1.19354 \dots)^{2} - 1.21612 \dots

3.1 (x - 1.19354 \dots)^{2} - 1.21612 \dots > 0

Move

1.21612 \dots

to the right side

3.1 (x - 1.19354 \dots)^{2} > 1.21612 \dots

Divide both sides by

3.1

(x - 1.19354 \dots)^{2} > 0.39229 \dots

For

u^{n} > a

, if

n

is even then

x - 1.19354 \dots < - 0.39229 \dots or x - 1.19354 \dots > 0.39229 \dots

x - 1.19354 \dots < - 0.39229 \dots : x < 0.56721 \dots

x - 1.19354 \dots > 0.39229 \dots : x > 1.81988 \dots

Combine the intervals

x < 0.56721 \dots or x > 1.81988 \dots

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N (4) = 1000 e^{0.01 (4)}

4 (x + 9) = 8 x - 7

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(\frac{9}{4})^{2}

\frac{x}{3} = \frac{x}{2}

simplify 8^{-2}*8^5 simplify

8^{- 2} \cdot 8^{5}

Frequently Asked Questions (FAQ)

What is 3.1x^2-7.4x+3.2>0 ?
The solution to 3.1x^2-7.4x+3.2>0 is x<0.56721…\lor x>1.81988…