What are the solutions to the equation 0=x^2+4x+3 ?

The solutions to the equation 0=x^2+4x+3 are x=-1,x=-3

Find the zeros of 0=x^2+4x+3

The zeros of 0=x^2+4x+3 are x=-1,x=-3

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0 = x^{2} + 4 x + 3

x = - 1, x = - 3

Solution steps

0 = x^{2} + 4 x + 3

Switch sides

x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2}{2 \cdot 1}

x = \frac{- 4 + 2}{2 \cdot 1} : - 1

x = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

100 - k^{2}

- 9 - 3

(\frac{t}{3})^{2}

- 36 r^{2} + 49

5 x + 1 = 9

What are the solutions to the equation 0=x^2+4x+3 ?
The solutions to the equation 0=x^2+4x+3 are x=-1,x=-3
Find the zeros of 0=x^2+4x+3
The zeros of 0=x^2+4x+3 are x=-1,x=-3