What are the solutions to the equation 3x^2-5x=3 ?

The solutions to the equation 3x^2-5x=3 are x=(5+sqrt(61))/6 ,x=(5-sqrt(61))/6

Find the zeros of 3x^2-5x=3

The zeros of 3x^2-5x=3 are x=(5+sqrt(61))/6 ,x=(5-sqrt(61))/6

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3 x^{2} - 5 x = 3

x = \frac{5 + 61}{6}, x = \frac{5 - 61}{6}

Decimal Notation

x = 2.13504 \dots, x = - 0.46837 \dots

Solution steps

3 x^{2} - 5 x = 3

Move

3

to the left side

3 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 3) = 61

x_{1, 2} = \frac{- ( - 5 ) \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 61}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 61}{2 \cdot 3}

x = \frac{- ( - 5 ) + 61}{2 \cdot 3} : \frac{5 + 61}{6}

x = \frac{- ( - 5 ) - 61}{2 \cdot 3} : \frac{5 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 61}{6}, x = \frac{5 - 61}{6}

3 a - 15

\frac{4}{4}

2 x^{2} + x - 21

12 < - 3 w

129 = - 1 - 10 R

What are the solutions to the equation 3x^2-5x=3 ?
The solutions to the equation 3x^2-5x=3 are x=(5+sqrt(61))/6 ,x=(5-sqrt(61))/6
Find the zeros of 3x^2-5x=3
The zeros of 3x^2-5x=3 are x=(5+sqrt(61))/6 ,x=(5-sqrt(61))/6