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Popular >

2|x+8|+15>27

Solution

2 ∣ x + 8 ∣ + 15 > 27

Solution

x < - 14 or x > - 2

+1

Interval Notation

(- \infty, - 14) \cup (- 2, \infty)

Solution steps

2 ∣ x + 8 ∣ + 15 > 27

Move

15

to the right side

2 ∣ x + 8 ∣ > 12

Divide both sides by

2

∣ x + 8 ∣ > 6

Apply absolute rule: If

∣ u ∣ > a, a > 0

then

u < - a

or

u > a

x + 8 < - 6 or x + 8 > 6

x + 8 < - 6 or x + 8 > 6

x < - 14 or x > - 2

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x^{2} + 7 x - 6 = 0

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(2 x^{3})^{3}

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(4 x + 3) (x - 6) = 0

∣ x - 3 ∣ + 2 x > 9

Frequently Asked Questions (FAQ)

What is 2|x+8|+15>27 ?
The solution to 2|x+8|+15>27 is x<-14\lor x>-2