What are the solutions to the equation 5z^2=17z-14 ?

The solutions to the equation 5z^2=17z-14 are z=2,z= 7/5

Find the zeros of 5z^2=17z-14

The zeros of 5z^2=17z-14 are z=2,z= 7/5

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5 z^{2} = 17 z - 14

z = 2, z = \frac{7}{5}

Decimal Notation

z = 2, z = 1.4

Solution steps

5 z^{2} = 17 z - 14

Move

14

to the left side

5 z^{2} + 14 = 17 z

Move

17 z

to the left side

5 z^{2} + 14 - 17 z = 0

Write in the standard form

a x^{2} + b x + c = 0

5 z^{2} - 17 z + 14 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 \cdot 14}{2 \cdot 5}

(- 17)^{2} - 4 \cdot 5 \cdot 14 = 3

z_{1, 2} = \frac{- ( - 17 ) \pm 3}{2 \cdot 5}

Separate the solutions

z_{1} = \frac{- ( - 17 ) + 3}{2 \cdot 5}, z_{2} = \frac{- ( - 17 ) - 3}{2 \cdot 5}

z = \frac{- ( - 17 ) + 3}{2 \cdot 5} : 2

z = \frac{- ( - 17 ) - 3}{2 \cdot 5} : \frac{7}{5}

The solutions to the quadratic equation are:

z = 2, z = \frac{7}{5}

\frac{( - 2 + 4 i )}{2 i}

- x + 5 < x + 3 \leq 2 x + 2

8 (m - 5) + 3 = 27

21 y^{2} - 2 y - 3

x (x - 4) (x + 1) \leq 0

What are the solutions to the equation 5z^2=17z-14 ?
The solutions to the equation 5z^2=17z-14 are z=2,z= 7/5
Find the zeros of 5z^2=17z-14
The zeros of 5z^2=17z-14 are z=2,z= 7/5