en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2|p+3|<= 14

Solution

2 ∣ p + 3 ∣ \leq 14

Solution

- 10 \leq p \leq 4

+1

Interval Notation

[- 10, 4]

Solution steps

2 ∣ p + 3 ∣ \leq 14

Divide both sides by

2

∣ p + 3 ∣ \leq 7

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 7 \leq p + 3 \leq 7

p + 3 \geq - 7 and p + 3 \leq 7

p \geq - 10 and p \leq 4

Merge Overlapping Intervals

- 10 \leq p \leq 4

Popular Examples

(x^{2} + 3) = 2 x - 5

simplify ((16sqrt(x))^2)/(y^{-1)}simplify

\frac{( 16 x ) ^{2}}{y ^{- 1}}

simplify (-2/3)^0 simplify

(- \frac{2}{3})^{0}

c - 7 \geq - 3

simplify 5/6-1/2 simplify

\frac{5}{6} - \frac{1}{2}

Frequently Asked Questions (FAQ)

What is 2|p+3|<= 14 ?
The solution to 2|p+3|<= 14 is -10<= p<= 4