What is (3x^{-3}y)^3*2xy^{-4} ?

The solution to (3x^{-3}y)^3*2xy^{-4} is (54)/(x^8y)

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simplify (3x^{-3}y)^3*2xy^{-4}

simplify

(3 x^{- 3} y)^{3} \cdot 2 x y^{- 4}

\frac{54}{x ^{8} y}

Solution steps

(3 x^{- 3} y)^{3} \cdot 2 x y^{- 4}

Simplify

(3 x^{- 3} y)^{3} : \frac{27 y ^{3}}{x ^{9}}

= \frac{27 y ^{3}}{x ^{9}} \cdot 2 x y^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 4} = \frac{1}{y ^{4}}

= \frac{27 y ^{3}}{x ^{9}} \cdot 2 x \frac{1}{y ^{4}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{27 y ^{3} \cdot 2 x \cdot 1}{x ^{9} y ^{4}}

Multiply the numbers:

27 \cdot 2 \cdot 1 = 54

= \frac{54 y ^{3} x}{x ^{9} y ^{4}}

Simplify

\frac{y ^{3}}{y ^{4}} : \frac{1}{y}

= \frac{54 x}{x ^{9} y}

Simplify

\frac{x}{x ^{9}} : \frac{1}{x ^{8}}

= \frac{54}{x ^{8} y}

z^{2} - 3 z - 9 = 0

7 + 3 a = 12 + 2 a

∣ x + 10 ∣ \leq 5

[6 - 2 w] < 10

\frac{4 x + 8}{x - 1} < 3

What is (3x^{-3}y)^3*2xy^{-4} ?
The solution to (3x^{-3}y)^3*2xy^{-4} is (54)/(x^8y)