What is (5+x)*(100-10x)>= 500 ?

The solution to (5+x)*(100-10x)>= 500 is 0<= x<= 5

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(5+x)*(100-10x)>= 500

(5 + x) \cdot (100 - 10 x) \geq 500

0 \leq x \leq 5

Interval Notation

[0, 5]

Solution steps

(5 + x) (100 - 10 x) \geq 500

Rewrite in standard form

- x^{2} + 5 x \geq 0

Factor

- x^{2} + 5 x : - x (x - 5)

- x (x - 5) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 5)) (- 1) \leq 0 \cdot (- 1)

Simplify

x (x - 5) \leq 0

Identify the intervals

0 \leq x \leq 5

121 x^{2} + 638 x - 32648

\frac{y}{3} + 1 = 5

4 x (x^{3} - 6) - 7 (x^{3} - 6)

\frac{8}{7}

5 a^{3} - 6 a^{2} + 45 a - 54

What is (5+x)*(100-10x)>= 500 ?
The solution to (5+x)*(100-10x)>= 500 is 0<= x<= 5