What are the solutions to the equation x^2+10x+3=0 ?

The solutions to the equation x^2+10x+3=0 are x=-5+sqrt(22),x=-5-sqrt(22)

Find the zeros of x^2+10x+3=0

The zeros of x^2+10x+3=0 are x=-5+sqrt(22),x=-5-sqrt(22)

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x^{2} + 10 x + 3 = 0

x = - 5 + 22, x = - 5 - 22

Decimal Notation

x = - 0.30958 \dots, x = - 9.69041 \dots

Solution steps

x^{2} + 10 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 3 = 222

x_{1, 2} = \frac{- 10 \pm 2 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 22}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 22}{2 \cdot 1}

x = \frac{- 10 + 2 22}{2 \cdot 1} : - 5 + 22

x = \frac{- 10 - 2 22}{2 \cdot 1} : - 5 - 22

The solutions to the quadratic equation are:

x = - 5 + 22, x = - 5 - 22

2 x = 128

- \frac{w}{4} = 20

8 < 2 x < x + 8

8 x^{2} - 2 x - 3 = 0

4 x - x^{2} > 4

What are the solutions to the equation x^2+10x+3=0 ?
The solutions to the equation x^2+10x+3=0 are x=-5+sqrt(22),x=-5-sqrt(22)
Find the zeros of x^2+10x+3=0
The zeros of x^2+10x+3=0 are x=-5+sqrt(22),x=-5-sqrt(22)