What are the solutions to the equation 4x^2-7x=0 ?

The solutions to the equation 4x^2-7x=0 are x= 7/4 ,x=0

Find the zeros of 4x^2-7x=0

The zeros of 4x^2-7x=0 are x= 7/4 ,x=0

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4 x^{2} - 7 x = 0

x = \frac{7}{4}, x = 0

Decimal Notation

x = 1.75, x = 0

Solution steps

4 x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 4}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 4}

x = \frac{- ( - 7 ) + 7}{2 \cdot 4} : \frac{7}{4}

x = \frac{- ( - 7 ) - 7}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = 0

ab - 3 b + b^{2} - 3 a

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∣ 4 ∣ x = 24

15 x^{3} - 6 + 18 x^{2} - 5 x

30 z^{2} - 53 z + 12

What are the solutions to the equation 4x^2-7x=0 ?
The solutions to the equation 4x^2-7x=0 are x= 7/4 ,x=0
Find the zeros of 4x^2-7x=0
The zeros of 4x^2-7x=0 are x= 7/4 ,x=0