What are the solutions to the equation 3x^2+12x-18=0 ?

The solutions to the equation 3x^2+12x-18=0 are x=-2+sqrt(10),x=-2-sqrt(10)

Find the zeros of 3x^2+12x-18=0

The zeros of 3x^2+12x-18=0 are x=-2+sqrt(10),x=-2-sqrt(10)

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3 x^{2} + 12 x - 18 = 0

x = - 2 + 10, x = - 2 - 10

Decimal Notation

x = 1.16227 \dots, x = - 5.16227 \dots

Solution steps

3 x^{2} + 12 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 18) = 610

x_{1, 2} = \frac{- 12 \pm 6 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 6 10}{2 \cdot 3}, x_{2} = \frac{- 12 - 6 10}{2 \cdot 3}

x = \frac{- 12 + 6 10}{2 \cdot 3} : - 2 + 10

x = \frac{- 12 - 6 10}{2 \cdot 3} : - 2 - 10

The solutions to the quadratic equation are:

x = - 2 + 10, x = - 2 - 10

3 \cdot 12

2 - \frac{3}{2}

2 = \frac{1}{8} (6 x - 24)

\frac{\frac{1}{9}}{2}

3 x^{2} + 2 x - 10 = 0

What are the solutions to the equation 3x^2+12x-18=0 ?
The solutions to the equation 3x^2+12x-18=0 are x=-2+sqrt(10),x=-2-sqrt(10)
Find the zeros of 3x^2+12x-18=0
The zeros of 3x^2+12x-18=0 are x=-2+sqrt(10),x=-2-sqrt(10)