What is factor 1/81 p-16p^5 ?

The solution to factor 1/81 p-16p^5 is -p(2p-1/3)(8p^3+(4p^2)/3+(2p)/9+1/27)

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factor 1/81 p-16p^5

factor

\frac{1}{81} p - 16 p^{5}

- p (2 p - \frac{1}{3}) (8 p^{3} + \frac{4 p ^{2}}{3} + \frac{2 p}{9} + \frac{1}{27})

Solution steps

\frac{1}{81} p - 16 p^{5}

Factor

\frac{p}{81} - 16 p^{5} : - p (2 p - \frac{1}{3}) (2^{3} p^{3} + \frac{1}{3} \cdot 2^{2} p^{2} + (\frac{1}{3})^{2} \cdot 2 p + (\frac{1}{3})^{3})

= - p (2 p - \frac{1}{3}) (2^{3} p^{3} + \frac{1}{3} \cdot 2^{2} p^{2} + (\frac{1}{3})^{2} \cdot 2 p + (\frac{1}{3})^{3})

Simplify

- p (2 p - \frac{1}{3}) (2^{3} p^{3} + \frac{1}{3} \cdot 2^{2} p^{2} + (\frac{1}{3})^{2} \cdot 2 p + (\frac{1}{3})^{3}) : - p (2 p - \frac{1}{3}) (8 p^{3} + \frac{4 p ^{2}}{3} + \frac{2 p}{9} + \frac{1}{27})

= - p (2 p - \frac{1}{3}) (8 p^{3} + \frac{4 p ^{2}}{3} + \frac{2 p}{9} + \frac{1}{27})

\frac{x ^{- 1} x ^{- 1}}{y ^{6} y ^{- 4}}

3 a (a + b + c) - 2 b (a + b + c) - c (a + b + c)

2 - x > 3

4^{\frac{- 3}{2}}

x - 5 \leq 3

What is factor 1/81 p-16p^5 ?
The solution to factor 1/81 p-16p^5 is -p(2p-1/3)(8p^3+(4p^2)/3+(2p)/9+1/27)