What are the solutions to the equation 10^2+8^2=x^2 ?

The solutions to the equation 10^2+8^2=x^2 are x=2sqrt(41),x=-2sqrt(41)

Find the zeros of 10^2+8^2=x^2

The zeros of 10^2+8^2=x^2 are x=2sqrt(41),x=-2sqrt(41)

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1 0^{2} + 8^{2} = x^{2}

x = 241, x = - 241

Decimal Notation

x = 12.80624 \dots, x = - 12.80624 \dots

Solution steps

1 0^{2} + 8^{2} = x^{2}

Switch sides

x^{2} = 1 0^{2} + 8^{2}

Simplify

1 0^{2} + 8^{2} : 164

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 164, x = - 164

164 = 241

- 164 = - 241

x = 241, x = - 241

3 - 8 ∣ 4 x + 3 ∣ = - 29

16 x^{2} + 8 x + 1

- 7 = \frac{9}{4} x

\frac{x + 4}{x - 2} < 0

(8 - 7 i)^{2}

What are the solutions to the equation 10^2+8^2=x^2 ?
The solutions to the equation 10^2+8^2=x^2 are x=2sqrt(41),x=-2sqrt(41)
Find the zeros of 10^2+8^2=x^2
The zeros of 10^2+8^2=x^2 are x=2sqrt(41),x=-2sqrt(41)