What are the solutions to the equation (x+1)(3x+4)=0 ?

The solutions to the equation (x+1)(3x+4)=0 are x=-1,x=-4/3

Find the zeros of (x+1)(3x+4)=0

The zeros of (x+1)(3x+4)=0 are x=-1,x=-4/3

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(x + 1) (3 x + 4) = 0

x = - 1, x = - \frac{4}{3}

Decimal Notation

x = - 1, x = - 1.33333 \dots

Solution steps

(x + 1) (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 3 x + 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{4}{3}

3 ∣ 5 x + 2 ∣ - 4 = 8

- \frac{7}{6} - \frac{14}{3}

3 (x + 2) = 8

6 x^{2} + 30 x - 84 = 0

\frac{- 65 \cdot 6}{65}

What are the solutions to the equation (x+1)(3x+4)=0 ?
The solutions to the equation (x+1)(3x+4)=0 are x=-1,x=-4/3
Find the zeros of (x+1)(3x+4)=0
The zeros of (x+1)(3x+4)=0 are x=-1,x=-4/3