What are the solutions to the equation 4x^2+23x+15=0 ?

The solutions to the equation 4x^2+23x+15=0 are x=-3/4 ,x=-5

Find the zeros of 4x^2+23x+15=0

The zeros of 4x^2+23x+15=0 are x=-3/4 ,x=-5

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4 x^{2} + 23 x + 15 = 0

x = - \frac{3}{4}, x = - 5

Decimal Notation

x = - 0.75, x = - 5

Solution steps

4 x^{2} + 23 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

2 3^{2} - 4 \cdot 4 \cdot 15 = 17

x_{1, 2} = \frac{- 23 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 23 + 17}{2 \cdot 4}, x_{2} = \frac{- 23 - 17}{2 \cdot 4}

x = \frac{- 23 + 17}{2 \cdot 4} : - \frac{3}{4}

x = \frac{- 23 - 17}{2 \cdot 4} : - 5

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 5

53 (3 - 2) + 3 (7 - 3)

(- 6 + 6 i) + (- 6 - 5 i)

2 x - \frac{π}{3} = 0

\frac{2 c}{3} + 1 > 7

x + 7 = (x + 5) (x + 2)

What are the solutions to the equation 4x^2+23x+15=0 ?
The solutions to the equation 4x^2+23x+15=0 are x=-3/4 ,x=-5
Find the zeros of 4x^2+23x+15=0
The zeros of 4x^2+23x+15=0 are x=-3/4 ,x=-5