What are the solutions to the equation 96x^2+12=0 ?

The solutions to the equation 96x^2+12=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i

Find the zeros of 96x^2+12=0

The zeros of 96x^2+12=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i

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96 x^{2} + 12 = 0

x = \frac{1}{2 2} i, x = - \frac{1}{2 2} i

Solution steps

96 x^{2} + 12 = 0

Move

12

to the right side

96 x^{2} = - 12

Divide both sides by

96

x^{2} = - \frac{1}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{8}, x = - - \frac{1}{8}

- \frac{1}{8} = \frac{1}{2 2} i

- - \frac{1}{8} = - \frac{1}{2 2} i

x = \frac{1}{2 2} i, x = - \frac{1}{2 2} i

10 - 2 (2 x - 4) = (3 x + 4) 2

0. 6^{3}

2 x^{2} + 9 x - 5

- 2 x^{2} + 8 x

\frac{10 k ^{2} + 30 k}{25 k ^{2}}

What are the solutions to the equation 96x^2+12=0 ?
The solutions to the equation 96x^2+12=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i
Find the zeros of 96x^2+12=0
The zeros of 96x^2+12=0 are x= 1/(2sqrt(2))i,x=-1/(2sqrt(2))i