What are the solutions to the equation -x^2+10x-24=0 ?

The solutions to the equation -x^2+10x-24=0 are x=4,x=6

Find the zeros of -x^2+10x-24=0

The zeros of -x^2+10x-24=0 are x=4,x=6

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- x^{2} + 10 x - 24 = 0

x = 4, x = 6

Solution steps

- x^{2} + 10 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 24 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 24) = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 ( - 1 )}, x_{2} = \frac{- 10 - 2}{2 ( - 1 )}

x = \frac{- 10 + 2}{2 ( - 1 )} : 4

x = \frac{- 10 - 2}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 4, x = 6

- 12 + 5 (7 p + 3) - 28 p < 3 p - 17

46 + 9 a = - 5 a + 74

2 (x + 3) = 14

4 \leq x < 6

18 x + 22 - 10 + 5 = - 22 x + 40 - 11

What are the solutions to the equation -x^2+10x-24=0 ?
The solutions to the equation -x^2+10x-24=0 are x=4,x=6
Find the zeros of -x^2+10x-24=0
The zeros of -x^2+10x-24=0 are x=4,x=6