What are the solutions to the equation 3x^2-6x+15=0 ?

The solutions to the equation 3x^2-6x+15=0 are x=1+2i,x=1-2i

Find the zeros of 3x^2-6x+15=0

The zeros of 3x^2-6x+15=0 are x=1+2i,x=1-2i

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3 x^{2} - 6 x + 15 = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

3 x^{2} - 6 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 15 : 12 i

x_{1, 2} = \frac{- ( - 6 ) \pm 12 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 12 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 12 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 12 i}{2 \cdot 3} : 1 + 2 i

x = \frac{- ( - 6 ) - 12 i}{2 \cdot 3} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

\frac{( 11 ) ^{2} + 64}{( 11 )}

3 x^{2} = 147

2 x - 3 \geq 4 x - 1

4 - (2 x - 3) = 3

4 (1 - x) + 3 x = - 2 (x + 1)

What are the solutions to the equation 3x^2-6x+15=0 ?
The solutions to the equation 3x^2-6x+15=0 are x=1+2i,x=1-2i
Find the zeros of 3x^2-6x+15=0
The zeros of 3x^2-6x+15=0 are x=1+2i,x=1-2i