What is the answer to (3x+1)(2x-3)=(2x+1)(3x-1) ?

The answer to (3x+1)(2x-3)=(2x+1)(3x-1) is x=-1/4

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(3x+1)(2x-3)=(2x+1)(3x-1)

(3 x + 1) (2 x - 3) = (2 x + 1) (3 x - 1)

x = - \frac{1}{4}

Decimal Notation

x = - 0.25

Solution steps

(3 x + 1) (2 x - 3) = (2 x + 1) (3 x - 1)

Expand

(3 x + 1) (2 x - 3) : 6 x^{2} - 7 x - 3

Expand

(2 x + 1) (3 x - 1) : 6 x^{2} + x - 1

6 x^{2} - 7 x - 3 = 6 x^{2} + x - 1

Move

3

to the right side

6 x^{2} - 7 x = 6 x^{2} + x + 2

Subtract

6 x^{2} + x

from both sides

6 x^{2} - 7 x - (6 x^{2} + x) = 6 x^{2} + x + 2 - (6 x^{2} + x)

Simplify

- 8 x = 2

Divide both sides by

- 8

x = - \frac{1}{4}

28 + 19 v = - 8 + 15 v

45 s^{4} - 36 s^{3} - 10 s + 8

x^{3} - 5 x^{2} - 14 x > 0

6 x^{2} - 2

3 x (4 m + 1) - 2 (4 m + 1)

What is the answer to (3x+1)(2x-3)=(2x+1)(3x-1) ?
The answer to (3x+1)(2x-3)=(2x+1)(3x-1) is x=-1/4
Solve for x: (3x+1)(2x-3)=(2x+1)(3x-1)
The solution is x=-1/4