What are the solutions to the equation 9x^2-7x=4 ?

The solutions to the equation 9x^2-7x=4 are x=(7+sqrt(193))/(18),x=(7-sqrt(193))/(18)

Find the zeros of 9x^2-7x=4

The zeros of 9x^2-7x=4 are x=(7+sqrt(193))/(18),x=(7-sqrt(193))/(18)

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9 x^{2} - 7 x = 4

x = \frac{7 + 193}{18}, x = \frac{7 - 193}{18}

Decimal Notation

x = 1.16069 \dots, x = - 0.38291 \dots

Solution steps

9 x^{2} - 7 x = 4

Move

4

to the left side

9 x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

(- 7)^{2} - 4 \cdot 9 (- 4) = 193

x_{1, 2} = \frac{- ( - 7 ) \pm 193}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 193}{2 \cdot 9}, x_{2} = \frac{- ( - 7 ) - 193}{2 \cdot 9}

x = \frac{- ( - 7 ) + 193}{2 \cdot 9} : \frac{7 + 193}{18}

x = \frac{- ( - 7 ) - 193}{2 \cdot 9} : \frac{7 - 193}{18}

The solutions to the quadratic equation are:

x = \frac{7 + 193}{18}, x = \frac{7 - 193}{18}

3^{5} \cdot 5^{3}

∣ 5 - 2 ∣ < 3

2 x^{2} - 72 x^{12}

\frac{1}{6} x = 10

- 67 + x \geq - 28

What are the solutions to the equation 9x^2-7x=4 ?
The solutions to the equation 9x^2-7x=4 are x=(7+sqrt(193))/(18),x=(7-sqrt(193))/(18)
Find the zeros of 9x^2-7x=4
The zeros of 9x^2-7x=4 are x=(7+sqrt(193))/(18),x=(7-sqrt(193))/(18)