What are the solutions to the equation 1x^2+5x+6=0 ?

The solutions to the equation 1x^2+5x+6=0 are x=-2,x=-3

Find the zeros of 1x^2+5x+6=0

The zeros of 1x^2+5x+6=0 are x=-2,x=-3

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1 x^{2} + 5 x + 6 = 0

x = - 2, x = - 3

Solution steps

1 \cdot x^{2} + 5 x + 6 = 0

Refine

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

63 x^{12} - 35 x^{6}

3 x - 1 = 20

\frac{x ^{- 4}}{x ^{- 9}}

X + 3 (X + 8) = 7 (X + 4)

4 x^{2} - 36 x + 81 = 0

What are the solutions to the equation 1x^2+5x+6=0 ?
The solutions to the equation 1x^2+5x+6=0 are x=-2,x=-3
Find the zeros of 1x^2+5x+6=0
The zeros of 1x^2+5x+6=0 are x=-2,x=-3