What are the solutions to the equation 0=-1/2 x^2+4x-2 ?

The solutions to the equation 0=-1/2 x^2+4x-2 are x=2(2-sqrt(3)),x=2(2+sqrt(3))

Find the zeros of 0=-1/2 x^2+4x-2

The zeros of 0=-1/2 x^2+4x-2 are x=2(2-sqrt(3)),x=2(2+sqrt(3))

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0 = - \frac{1}{2} x^{2} + 4 x - 2

x = 2 (2 - 3), x = 2 (2 + 3)

Decimal Notation

x = 0.53589 \dots, x = 7.46410 \dots

Solution steps

0 = - \frac{1}{2} x^{2} + 4 x - 2

Multiply both sides by

2

0 = - x^{2} + 8 x - 4

Switch sides

- x^{2} + 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 4) = 43

x_{1, 2} = \frac{- 8 \pm 4 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 3}{2 ( - 1 )}, x_{2} = \frac{- 8 - 4 3}{2 ( - 1 )}

x = \frac{- 8 + 4 3}{2 ( - 1 )} : 2 (2 - 3)

x = \frac{- 8 - 4 3}{2 ( - 1 )} : 2 (2 + 3)

The solutions to the quadratic equation are:

x = 2 (2 - 3), x = 2 (2 + 3)

- 172 \leq 2 s

5 x^{\frac{5}{4}}

11 x - 37 = 6 (x + 33)

- x^{2} - 4 x - 5 \leq - 2

x^{2} = x + 3

What are the solutions to the equation 0=-1/2 x^2+4x-2 ?
The solutions to the equation 0=-1/2 x^2+4x-2 are x=2(2-sqrt(3)),x=2(2+sqrt(3))
Find the zeros of 0=-1/2 x^2+4x-2
The zeros of 0=-1/2 x^2+4x-2 are x=2(2-sqrt(3)),x=2(2+sqrt(3))