What are the solutions to the equation 3x^2+10x-8=0 ?

The solutions to the equation 3x^2+10x-8=0 are x= 2/3 ,x=-4

Find the zeros of 3x^2+10x-8=0

The zeros of 3x^2+10x-8=0 are x= 2/3 ,x=-4

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3 x^{2} + 10 x - 8 = 0

x = \frac{2}{3}, x = - 4

Decimal Notation

x = 0.66666 \dots, x = - 4

Solution steps

3 x^{2} + 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 8) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 3}, x_{2} = \frac{- 10 - 14}{2 \cdot 3}

x = \frac{- 10 + 14}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 10 - 14}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 4

- 4 = 4 x^{2} + 3 x - 6

(6 g^{4} h^{5})^{2}

x^{2} - 256 y^{2}

(0 - 1)^{2} + (y + 8)^{2} = 4

\frac{x ^{2} - 4 x + 3}{x ^{2} - 6 x + 8} > 0

What are the solutions to the equation 3x^2+10x-8=0 ?
The solutions to the equation 3x^2+10x-8=0 are x= 2/3 ,x=-4
Find the zeros of 3x^2+10x-8=0
The zeros of 3x^2+10x-8=0 are x= 2/3 ,x=-4