What are the solutions to the equation 0=x^2-4 ?

The solutions to the equation 0=x^2-4 are x=2,x=-2

Find the zeros of 0=x^2-4

The zeros of 0=x^2-4 are x=2,x=-2

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0 = x^{2} - 4

x = 2, x = - 2

Solution steps

0 = x^{2} - 4

Switch sides

x^{2} - 4 = 0

Move

4

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

(3 x + 4)^{2} = 14

\frac{7 ^{5}}{7 ^{3}}

2 n^{2} - 8 n^{3}

x^{2} - 48 = 0

m^{2} + 10 m + 9 = 0

What are the solutions to the equation 0=x^2-4 ?
The solutions to the equation 0=x^2-4 are x=2,x=-2
Find the zeros of 0=x^2-4
The zeros of 0=x^2-4 are x=2,x=-2