What is factor 28y^2+43y-48 ?

The solution to factor 28y^2+43y-48 is (4y-3)(7y+16)

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factor 28y^2+43y-48

factor

28 y^{2} + 43 y - 48

(4 y - 3) (7 y + 16)

Solution steps

28 y^{2} + 43 y - 48

Break the expression into groups

= (28 y^{2} - 21 y) + (64 y - 48)

Factor out

7 y

from

28 y^{2} - 21 y : 7 y (4 y - 3)

Factor out

16

from

64 y - 48 : 16 (4 y - 3)

= 7 y (4 y - 3) + 16 (4 y - 3)

Factor out common term

4 y - 3

= (4 y - 3) (7 y + 16)

x^{\frac{3}{2}} - x^{\frac{1}{2}}

25 w^{2} - 9 u^{2}

4 (- 4 x + 4) = - 8 (- 2 + 2 x)

- p - 4 p > - 10

x^{2} - 14 x = - 40

What is factor 28y^2+43y-48 ?
The solution to factor 28y^2+43y-48 is (4y-3)(7y+16)