What are the solutions to the equation x^2-12x+24=0 ?

The solutions to the equation x^2-12x+24=0 are x=2(3+sqrt(3)),x=2(3-sqrt(3))

Find the zeros of x^2-12x+24=0

The zeros of x^2-12x+24=0 are x=2(3+sqrt(3)),x=2(3-sqrt(3))

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x^{2} - 12 x + 24 = 0

x = 2 (3 + 3), x = 2 (3 - 3)

Decimal Notation

x = 9.46410 \dots, x = 2.53589 \dots

Solution steps

x^{2} - 12 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 24 = 43

x_{1, 2} = \frac{- ( - 12 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 3}{2 \cdot 1} : 2 (3 + 3)

x = \frac{- ( - 12 ) - 4 3}{2 \cdot 1} : 2 (3 - 3)

The solutions to the quadratic equation are:

x = 2 (3 + 3), x = 2 (3 - 3)

- 6 < x < 5

∣ - 4 ∣

x^{3} + 2 x^{2} - 16 x - 32

7 x + 39 \geq 53 and 16 x + 15 > 31

∣ 8 z - 4 ∣ = 6

What are the solutions to the equation x^2-12x+24=0 ?
The solutions to the equation x^2-12x+24=0 are x=2(3+sqrt(3)),x=2(3-sqrt(3))
Find the zeros of x^2-12x+24=0
The zeros of x^2-12x+24=0 are x=2(3+sqrt(3)),x=2(3-sqrt(3))