What are the solutions to the equation -7x^2-23x+10=0 ?

The solutions to the equation -7x^2-23x+10=0 are x=-(23+sqrt(809))/(14),x=(sqrt(809)-23)/(14)

Find the zeros of -7x^2-23x+10=0

The zeros of -7x^2-23x+10=0 are x=-(23+sqrt(809))/(14),x=(sqrt(809)-23)/(14)

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- 7 x^{2} - 23 x + 10 = 0

x = - \frac{23 + 809}{14}, x = \frac{809 - 23}{14}

Decimal Notation

x = - 3.67449 \dots, x = 0.38878 \dots

Solution steps

- 7 x^{2} - 23 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 ( - 7 ) \cdot 10}{2 ( - 7 )}

(- 23)^{2} - 4 (- 7) \cdot 10 = 809

x_{1, 2} = \frac{- ( - 23 ) \pm 809}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 809}{2 ( - 7 )}, x_{2} = \frac{- ( - 23 ) - 809}{2 ( - 7 )}

x = \frac{- ( - 23 ) + 809}{2 ( - 7 )} : - \frac{23 + 809}{14}

x = \frac{- ( - 23 ) - 809}{2 ( - 7 )} : \frac{809 - 23}{14}

The solutions to the quadratic equation are:

x = - \frac{23 + 809}{14}, x = \frac{809 - 23}{14}

7^{\frac{1}{2}} \cdot 7^{\frac{1}{2}}

- (2^{3})

(- \frac{5}{3})^{- 3}

6 a^{3} - 21 a^{2} b + 2 a b^{2} - 7 b^{3}

8 x - 5 = 6 x + 1

What are the solutions to the equation -7x^2-23x+10=0 ?
The solutions to the equation -7x^2-23x+10=0 are x=-(23+sqrt(809))/(14),x=(sqrt(809)-23)/(14)
Find the zeros of -7x^2-23x+10=0
The zeros of -7x^2-23x+10=0 are x=-(23+sqrt(809))/(14),x=(sqrt(809)-23)/(14)