What are the solutions to the equation 5(x-1)^2-39=-19 ?

The solutions to the equation 5(x-1)^2-39=-19 are x=3,x=-1

Find the zeros of 5(x-1)^2-39=-19

The zeros of 5(x-1)^2-39=-19 are x=3,x=-1

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5 (x - 1)^{2} - 39 = - 19

x = 3, x = - 1

Solution steps

5 (x - 1)^{2} - 39 = - 19

Move

39

to the right side

5 (x - 1)^{2} = 20

Divide both sides by

5

(x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 4 : x = 3

Solve

x - 1 = - 4 : x = - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

(25 m^{2} - 20 mn + 4 n^{2}) - 36 p^{2}

x + 8 = 12

0 = x^{2} + 2 x - 24

7 x - (2 - 3 x) = 5 x + 43

What are the solutions to the equation 5(x-1)^2-39=-19 ?
The solutions to the equation 5(x-1)^2-39=-19 are x=3,x=-1
Find the zeros of 5(x-1)^2-39=-19
The zeros of 5(x-1)^2-39=-19 are x=3,x=-1