What are the solutions to the equation 9y^2-6y+1=0 ?

The solutions to the equation 9y^2-6y+1=0 are y= 1/3

Find the zeros of 9y^2-6y+1=0

The zeros of 9y^2-6y+1=0 are y= 1/3

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9 y^{2} - 6 y + 1 = 0

y = \frac{1}{3}

Decimal Notation

y = 0.33333 \dots

Solution steps

9 y^{2} - 6 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 \cdot 1 = 0

y_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 9}

y = \frac{- ( - 6 )}{2 \cdot 9}

\frac{- ( - 6 )}{2 \cdot 9} = \frac{1}{3}

y = \frac{1}{3}

The solution to the quadratic equation is:

y = \frac{1}{3}

5 x^{2} - 18 x + 4 = 12 x + 39

x^{2} = 43

(\frac{125}{64})^{- \frac{2}{3}}

x^{3} + x^{2} + 3 x + 3

36 r^{3} + 30 r^{2} - 30 r - 25

What are the solutions to the equation 9y^2-6y+1=0 ?
The solutions to the equation 9y^2-6y+1=0 are y= 1/3
Find the zeros of 9y^2-6y+1=0
The zeros of 9y^2-6y+1=0 are y= 1/3