What are the solutions to the equation -2x^2+25=7 ?

The solutions to the equation -2x^2+25=7 are x=3,x=-3

Find the zeros of -2x^2+25=7

The zeros of -2x^2+25=7 are x=3,x=-3

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- 2 x^{2} + 25 = 7

x = 3, x = - 3

Solution steps

- 2 x^{2} + 25 = 7

Move

25

to the right side

- 2 x^{2} = - 18

Divide both sides by

- 2

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

\frac{t}{2} \leq 2

\frac{( 4 - 2 x )}{5 x + 2} \leq 0

- 6 - (- 1)

6 x + 2 = 9 x - 4

2 x^{2} + x + 1 = 0

What are the solutions to the equation -2x^2+25=7 ?
The solutions to the equation -2x^2+25=7 are x=3,x=-3
Find the zeros of -2x^2+25=7
The zeros of -2x^2+25=7 are x=3,x=-3