What are the solutions to the equation -2x^2+112=14 ?

The solutions to the equation -2x^2+112=14 are x=7,x=-7

Find the zeros of -2x^2+112=14

The zeros of -2x^2+112=14 are x=7,x=-7

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- 2 x^{2} + 112 = 14

x = 7, x = - 7

Solution steps

- 2 x^{2} + 112 = 14

Move

112

to the right side

- 2 x^{2} = - 98

Divide both sides by

- 2

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

s^{2} - 5 s + 4

3 x = 2 x + 3

\frac{7}{3} + \frac{1}{2}

∣ 2 x - 3 ∣ = 5

x^{2} - 10 x + 74 = 0

What are the solutions to the equation -2x^2+112=14 ?
The solutions to the equation -2x^2+112=14 are x=7,x=-7
Find the zeros of -2x^2+112=14
The zeros of -2x^2+112=14 are x=7,x=-7