What are the solutions to the equation 20s^2+s-10=2 ?

The solutions to the equation 20s^2+s-10=2 are s= 3/4 ,s=-4/5

Find the zeros of 20s^2+s-10=2

The zeros of 20s^2+s-10=2 are s= 3/4 ,s=-4/5

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20 s^{2} + s - 10 = 2

s = \frac{3}{4}, s = - \frac{4}{5}

Decimal Notation

s = 0.75, s = - 0.8

Solution steps

20 s^{2} + s - 10 = 2

Move

2

to the left side

20 s^{2} + s - 12 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 20 ( - 12 )}{2 \cdot 20}

1^{2} - 4 \cdot 20 (- 12) = 31

s_{1, 2} = \frac{- 1 \pm 31}{2 \cdot 20}

Separate the solutions

s_{1} = \frac{- 1 + 31}{2 \cdot 20}, s_{2} = \frac{- 1 - 31}{2 \cdot 20}

s = \frac{- 1 + 31}{2 \cdot 20} : \frac{3}{4}

s = \frac{- 1 - 31}{2 \cdot 20} : - \frac{4}{5}

The solutions to the quadratic equation are:

s = \frac{3}{4}, s = - \frac{4}{5}

3 x > - 15

\frac{3}{4} + \frac{9}{10}

- 43 + 5 m = - 73

x^{4} - 81

- x = 0

What are the solutions to the equation 20s^2+s-10=2 ?
The solutions to the equation 20s^2+s-10=2 are s= 3/4 ,s=-4/5
Find the zeros of 20s^2+s-10=2
The zeros of 20s^2+s-10=2 are s= 3/4 ,s=-4/5