What are the solutions to the equation y^2+9y=-14 ?

The solutions to the equation y^2+9y=-14 are y=-2,y=-7

Find the zeros of y^2+9y=-14

The zeros of y^2+9y=-14 are y=-2,y=-7

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y^{2} + 9 y = - 14

y = - 2, y = - 7

Solution steps

y^{2} + 9 y = - 14

Move

14

to the left side

y^{2} + 9 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 14 = 5

y_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 9 + 5}{2 \cdot 1}, y_{2} = \frac{- 9 - 5}{2 \cdot 1}

y = \frac{- 9 + 5}{2 \cdot 1} : - 2

y = \frac{- 9 - 5}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = - 2, y = - 7

2 \cdot 5

\frac{( 3 + i )}{3 - i}

- 12 r - 28 \leq - 4 (2 r + 9)

25 - (2 + x)^{2}

- \frac{5}{6} x + 3 < - \frac{1}{2}

What are the solutions to the equation y^2+9y=-14 ?
The solutions to the equation y^2+9y=-14 are y=-2,y=-7
Find the zeros of y^2+9y=-14
The zeros of y^2+9y=-14 are y=-2,y=-7