What is factor 16x^2-40x+25 ?

The solution to factor 16x^2-40x+25 is (4x-5)^2

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factor 16x^2-40x+25

factor

16 x^{2} - 40 x + 25

(4 x - 5)^{2}

Solution steps

16 x^{2} - 40 x + 25

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 x^{2} = (4 x)^{2}

25 = 5^{2}

- 40 x = - 2 \cdot 4 x \cdot 5

= (4 x)^{2} - 2 \cdot 4 x \cdot 5 + 5^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(4 x)^{2} - 2 \cdot 4 x \cdot 5 + 5^{2} = (4 x - 5)^{2}

= (4 x - 5)^{2}

222

\frac{- 3 ( x + 3 )}{2} \leq 6

y^{2} + 8 y + 12

49 - 64 x^{2}

6 ∣ 1 - 5 x ∣ - 9 = 57