What is the answer to 4n+2=6(31n-32) ?

The answer to 4n+2=6(31n-32) is n= 97/91

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4n+2=6(31n-32)

4 n + 2 = 6 (31 n - 32)

n = \frac{97}{91}

Decimal Notation

n = 1.06593 \dots

Solution steps

4 n + 2 = 6 (31 n - 32)

Expand

6 (31 n - 32) : 186 n - 192

4 n + 2 = 186 n - 192

Move

2

to the right side

4 n = 186 n - 194

Move

186 n

to the left side

- 182 n = - 194

Divide both sides by

- 182

n = \frac{97}{91}

\frac{8}{i}

\frac{5}{9} - \frac{1}{2}

3 x^{2} - 12 x = 0

- 14 p^{3} q^{3} - 21 p^{2} q^{2} + 35 pq

- 4.905 x^{2} + 90 x + 150 = 0