What are the solutions to the equation -8x^2+3x+2=0 ?

The solutions to the equation -8x^2+3x+2=0 are x=-(-3+sqrt(73))/(16),x=(3+sqrt(73))/(16)

Find the zeros of -8x^2+3x+2=0

The zeros of -8x^2+3x+2=0 are x=-(-3+sqrt(73))/(16),x=(3+sqrt(73))/(16)

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- 8 x^{2} + 3 x + 2 = 0

x = - \frac{- 3 + 73}{16}, x = \frac{3 + 73}{16}

Decimal Notation

x = - 0.34650 \dots, x = 0.72150 \dots

Solution steps

- 8 x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 8 ) \cdot 2}{2 ( - 8 )}

3^{2} - 4 (- 8) \cdot 2 = 73

x_{1, 2} = \frac{- 3 \pm 73}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 3 + 73}{2 ( - 8 )}, x_{2} = \frac{- 3 - 73}{2 ( - 8 )}

x = \frac{- 3 + 73}{2 ( - 8 )} : - \frac{- 3 + 73}{16}

x = \frac{- 3 - 73}{2 ( - 8 )} : \frac{3 + 73}{16}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 73}{16}, x = \frac{3 + 73}{16}

\frac{1}{1 - 2 i}

\frac{5 + x}{9} = \frac{x - 11}{6}

n - 1 > 3

∣ - 7 ∣ + 9

(x - 2) y - (x - 2) z

What are the solutions to the equation -8x^2+3x+2=0 ?
The solutions to the equation -8x^2+3x+2=0 are x=-(-3+sqrt(73))/(16),x=(3+sqrt(73))/(16)
Find the zeros of -8x^2+3x+2=0
The zeros of -8x^2+3x+2=0 are x=-(-3+sqrt(73))/(16),x=(3+sqrt(73))/(16)