What are the solutions to the equation x^2-14x=-48 ?

The solutions to the equation x^2-14x=-48 are x=8,x=6

Find the zeros of x^2-14x=-48

The zeros of x^2-14x=-48 are x=8,x=6

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x^{2} - 14 x = - 48

x = 8, x = 6

Solution steps

x^{2} - 14 x = - 48

Move

48

to the left side

x^{2} - 14 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 48 = 2

x_{1, 2} = \frac{- ( - 14 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2}{2 \cdot 1} : 8

x = \frac{- ( - 14 ) - 2}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 8, x = 6

- 5 < x < 0

\frac{2}{5} - \frac{3}{8} + \frac{5}{6}

∣ x - 1 ∣ < ∣ 2 x + 1 ∣

121 x^{2} - 144 y^{2}

(y - 3)^{2} - 64

What are the solutions to the equation x^2-14x=-48 ?
The solutions to the equation x^2-14x=-48 are x=8,x=6
Find the zeros of x^2-14x=-48
The zeros of x^2-14x=-48 are x=8,x=6