What are the solutions to the equation 5x^2+2x+8=0 ?

The solutions to the equation 5x^2+2x+8=0 are x=-1/5+i(sqrt(39))/5 ,x=-1/5-i(sqrt(39))/5

Find the zeros of 5x^2+2x+8=0

The zeros of 5x^2+2x+8=0 are x=-1/5+i(sqrt(39))/5 ,x=-1/5-i(sqrt(39))/5

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5 x^{2} + 2 x + 8 = 0

x = - \frac{1}{5} + i \frac{39}{5}, x = - \frac{1}{5} - i \frac{39}{5}

Solution steps

5 x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

2^{2} - 4 \cdot 5 \cdot 8 : 239 i

x_{1, 2} = \frac{- 2 \pm 2 39 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 2 39 i}{2 \cdot 5}, x_{2} = \frac{- 2 - 2 39 i}{2 \cdot 5}

x = \frac{- 2 + 2 39 i}{2 \cdot 5} : - \frac{1}{5} + i \frac{39}{5}

x = \frac{- 2 - 2 39 i}{2 \cdot 5} : - \frac{1}{5} - i \frac{39}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{39}{5}, x = - \frac{1}{5} - i \frac{39}{5}

(x^{\frac{1}{3}})^{5}

x^{2} + 12 x - 9 = 0

j + 7 = 23

3 [m - 7] + 9 > - 30

\frac{3}{7} \cdot \frac{4}{5}

What are the solutions to the equation 5x^2+2x+8=0 ?
The solutions to the equation 5x^2+2x+8=0 are x=-1/5+i(sqrt(39))/5 ,x=-1/5-i(sqrt(39))/5
Find the zeros of 5x^2+2x+8=0
The zeros of 5x^2+2x+8=0 are x=-1/5+i(sqrt(39))/5 ,x=-1/5-i(sqrt(39))/5