What is factor n^2-4n-21 ?

The solution to factor n^2-4n-21 is (n+3)(n-7)

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factor n^2-4n-21

factor

n^{2} - 4 n - 21

(n + 3) (n - 7)

Solution steps

n^{2} - 4 n - 21

Break the expression into groups

= (n^{2} + 3 n) + (- 7 n - 21)

Factor out

n

from

n^{2} + 3 n : n (n + 3)

Factor out

- 7

from

- 7 n - 21 : - 7 (n + 3)

= n (n + 3) - 7 (n + 3)

Factor out common term

n + 3

= (n + 3) (n - 7)

\frac{21}{- 7}

- \frac{1}{2} - \frac{3}{5}

\frac{12 a ^{4} b ^{5}}{4 a ^{3} b ^{6}}

(\frac{0.02}{365})^{365 \cdot 3}

(32)^{2}