What are the solutions to the equation 3y^2-4y-2=0 ?

The solutions to the equation 3y^2-4y-2=0 are y=(2+sqrt(10))/3 ,y=(2-sqrt(10))/3

Find the zeros of 3y^2-4y-2=0

The zeros of 3y^2-4y-2=0 are y=(2+sqrt(10))/3 ,y=(2-sqrt(10))/3

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3 y^{2} - 4 y - 2 = 0

y = \frac{2 + 10}{3}, y = \frac{2 - 10}{3}

Decimal Notation

y = 1.72075 \dots, y = - 0.38742 \dots

Solution steps

3 y^{2} - 4 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 2) = 210

y_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 3}, y_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 3}

y = \frac{- ( - 4 ) + 2 10}{2 \cdot 3} : \frac{2 + 10}{3}

y = \frac{- ( - 4 ) - 2 10}{2 \cdot 3} : \frac{2 - 10}{3}

The solutions to the quadratic equation are:

y = \frac{2 + 10}{3}, y = \frac{2 - 10}{3}

2 - 2 i

9 < 3 (- \frac{1}{3} p + 6)

\frac{468}{7} - 67

(x + h)^{3} - x^{3}

What are the solutions to the equation 3y^2-4y-2=0 ?
The solutions to the equation 3y^2-4y-2=0 are y=(2+sqrt(10))/3 ,y=(2-sqrt(10))/3
Find the zeros of 3y^2-4y-2=0
The zeros of 3y^2-4y-2=0 are y=(2+sqrt(10))/3 ,y=(2-sqrt(10))/3