What are the solutions to the equation 7x^2-28=0 ?

The solutions to the equation 7x^2-28=0 are x=2,x=-2

Find the zeros of 7x^2-28=0

The zeros of 7x^2-28=0 are x=2,x=-2

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7 x^{2} - 28 = 0

x = 2, x = - 2

Solution steps

7 x^{2} - 28 = 0

Move

28

to the right side

7 x^{2} = 28

Divide both sides by

7

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

- x^{2} + 3 x - 6 + 9 > 3 x - 6 + 2 x^{2}

- 6 x^{2} + 24 x

∣ x - 11 ∣ = ∣ 2 x + 11 ∣

\frac{2 x - 6}{x + 5} \leq 0

x^{3} + 5 x^{2} - 16 x - 80

What are the solutions to the equation 7x^2-28=0 ?
The solutions to the equation 7x^2-28=0 are x=2,x=-2
Find the zeros of 7x^2-28=0
The zeros of 7x^2-28=0 are x=2,x=-2