What are the solutions to the equation b^2+2b+4=0 ?

The solutions to the equation b^2+2b+4=0 are b=-1+sqrt(3)i,b=-1-sqrt(3)i

Find the zeros of b^2+2b+4=0

The zeros of b^2+2b+4=0 are b=-1+sqrt(3)i,b=-1-sqrt(3)i

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b^{2} + 2 b + 4 = 0

b = - 1 + 3 i, b = - 1 - 3 i

Solution steps

b^{2} + 2 b + 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

b_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, b_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

b = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

b = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

b = - 1 + 3 i, b = - 1 - 3 i

1 + 4 x^{4} + 4 x^{2}

\frac{4 m + 36}{m + 9} \cdot \frac{m - 5}{5 m ^{2}}

3 2^{3}

0.0611 (1352 - x) (1770 - x) = x^{2}

5 x + 50 < x^{2}

What are the solutions to the equation b^2+2b+4=0 ?
The solutions to the equation b^2+2b+4=0 are b=-1+sqrt(3)i,b=-1-sqrt(3)i
Find the zeros of b^2+2b+4=0
The zeros of b^2+2b+4=0 are b=-1+sqrt(3)i,b=-1-sqrt(3)i