What are the solutions to the equation 4x^2-4x-24=0 ?

The solutions to the equation 4x^2-4x-24=0 are x=3,x=-2

Find the zeros of 4x^2-4x-24=0

The zeros of 4x^2-4x-24=0 are x=3,x=-2

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4 x^{2} - 4 x - 24 = 0

x = 3, x = - 2

Solution steps

4 x^{2} - 4 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 24) = 20

x_{1, 2} = \frac{- ( - 4 ) \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 20}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 20}{2 \cdot 4}

x = \frac{- ( - 4 ) + 20}{2 \cdot 4} : 3

x = \frac{- ( - 4 ) - 20}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

\frac{( x ^{\frac{2}{3}} y ^{\frac{3}{2}} ) ^{2}}{x ^{\frac{4}{3}} y ^{3}}

(5 v - 6) (4 + v) = 0

\frac{i ^{2}}{e}

2 + 8 x = 4 - 5 x

What are the solutions to the equation 4x^2-4x-24=0 ?
The solutions to the equation 4x^2-4x-24=0 are x=3,x=-2
Find the zeros of 4x^2-4x-24=0
The zeros of 4x^2-4x-24=0 are x=3,x=-2