What is the answer to 1/3 (6-3x)+1/4 (x-1)(x-2)=(x^2)/4 ?

The answer to 1/3 (6-3x)+1/4 (x-1)(x-2)=(x^2)/4 is x= 10/7

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1/3 (6-3x)+1/4 (x-1)(x-2)=(x^2)/4

\frac{1}{3} (6 - 3 x) + \frac{1}{4} (x - 1) (x - 2) = \frac{x ^{2}}{4}

x = \frac{10}{7}

Decimal Notation

x = 1.42857 \dots

Solution steps

\frac{1}{3} (6 - 3 x) + \frac{1}{4} (x - 1) (x - 2) = \frac{x ^{2}}{4}

\frac{1}{3} (6 - 3 x) = \frac{6 - 3 x}{3}

\frac{6 - 3 x}{3} + \frac{1}{4} (x - 1) (x - 2) = \frac{x ^{2}}{4}

Multiply by LCM

12 (2 - x) + 3 (x - 1) (x - 2) = 3 x^{2}

Expand

12 (2 - x) + 3 (x - 1) (x - 2) : 3 x^{2} - 21 x + 30

3 x^{2} - 21 x + 30 = 3 x^{2}

Move

30

to the right side

3 x^{2} - 21 x = 3 x^{2} - 30

Move

3 x^{2}

to the left side

- 21 x = - 30

Divide both sides by

- 21

x = \frac{10}{7}

2 t^{2} + 13 t + 6

3 x^{2} - 5 x + 3 > 2 x^{2} + x - 4

x^{\frac{1}{4}} \cdot x^{\frac{1}{2}}

r - 2 = 5

e^{1} + e^{- 1}

What is the answer to 1/3 (6-3x)+1/4 (x-1)(x-2)=(x^2)/4 ?
The answer to 1/3 (6-3x)+1/4 (x-1)(x-2)=(x^2)/4 is x= 10/7
Solve for x: 1/3 (6-3x)+1/4 (x-1)(x-2)=(x^2)/4
The solution is x= 10/7